MATRIX SCRIPT
Neo has a complex matrix script. The matrix script is a X grid of strings. It consists of alphanumeric characters, spaces and symbols (!,@,#,$,%,&).
To decode the script, Neo needs to read each column and select only the alphanumeric characters and connect them. Neo reads the column from top to bottom and starts reading from the leftmost column.
If there are symbols or spaces between two alphanumeric characters of the decoded script, then Neo replaces them with a single space '' for better readability.
Neo feels that there is no need to use 'if' conditions for decoding.
Alphanumeric characters consist of: [A-Z, a-z, and 0-9].
Input Format
The first line contains space-separated integers (rows) and (columns) respectively.
The next lines contain the row elements of the matrix script.
Constraints
Note: A score will be awarded for using 'if' conditions in your code.
Output Format
Print the decoded matrix script.
Sample Input 0
7 3
Tsi
h%x
i #
sM
$a
#t%
ir!
Sample Output 0
This is Matrix# %!
Explanation 0
The decoded script is:
This$#is% Matrix# %!
Neo replaces the symbols or spaces between two alphanumeric characters with a single space ' ' for better readability.
So, the final decoded script is:
This is Matrix# %!CODE:first_multiple_input = input().rstrip().split()
n = int(first_multiple_input[0])
m = int(first_multiple_input[1])
matrix = []
for _ in range(n):
matrix_item = input()
matrix.append(matrix_item)
#print(matrix)
a=[]
# a will be the decoded script
for i in range(m):
for j in range(n):
a.append(matrix[j][i])
#print(a)
special_chr='!,@,#,$,%,&'
i=0
b=''#final script
while i!=len(a):
state=False
#if special character found then check if onwards the string has alnum char
#else add chr to b
if a[i] in special_chr:
s=a[i+1:]
for j in range(len(s)):
#if no alnum chr in rest of list then add special chr to b
#if alnum found continue indexing from this alnum position(i+=j) i.e skipping rest of special chr so space only added once
if s[j].isalnum():
state=True
b+=' '
i+=j
break
if not state:
b+=a[i]
else:
b+=a[i]
i+=1
print(b)
Comments
Post a Comment